Ziya

Ziya
@TryingToUnderstand
What if not? nullius in verba/memento mori/omnes una manet nox/sub specie aeternitatis #130893017 #135188298 #133405446 #134412952
yaşamak
CE, GTU
soluk mavi nokta
Eskişehir, 18 Nisan
9 kütüphaneci puanı
511 okur puanı
Haziran 2021 tarihinde katıldı
A laser printer utilizes the forces between charged bodies. The printer’s light-sensitive imaging drum is given a positive charge. As the drum rotates, a laser beam shines on selected areas of the drum, leaving those areas with a negative charge. Positively charged particles of toner adhere only to the areas of the drum “written” by the laser. When a piece of paper is placed in contact with the drum, the toner particles stick to the paper and form an image.
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Ziya

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Puan vermedi·682 syf.·
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Okunma: 04 Mart 2023 15:56
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2023 6. kitabı
Hugh D. Young
9.7/10 · 11 okunma
The ancient Greeks discovered as early as 600 b.c. that after they rubbed amber with wool, the amber could attract other objects. Today we say that the amber has acquired a net electric charge, or has become charged. The word “electric” is derived from the Greek word elektron, meaning amber.
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printf içinde şartlı operatör
It is not necessary that the conditional operator be used on the right-hand side of an assignment—it can be used in any situation in which an expression could be used. This means that you could display the sign of the variable number, without first assigning it to a variable, using a printf statement as shown: printf ("Sign = %i\n", ( number < 0 ) ? –1 : ( number == 0 ) ? 0 : 1);
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şartlı operatörle else if yaratmak
sign = ( number < 0 ) ? -1 : (( number == 0 ) ? 0 : 1); If number is less than zero, sign is assigned the value –1; else if number is equal to zero, sign is assigned the value 0; else it is assigned the value 1.The parentheses around the “else” part of the preceding expression are actually unnecessary.This is because the conditional operator associates from right to left, meaning that multiple uses of this operator in a single expression, such as in e1 ? e2 : e3 ? e4 : e5 group from right to left and, therefore, are evaluated as e1 ? e2 : ( e3 ? e4 : e5 )
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